36 exam-style questions on Transformations of graphs — topic 2.10 of Functions in the IB Mathematics: Analysis and Approaches syllabus — with answers and explanations. Samples below; the full set is free with an account.
Compared with y = f(x), the graph of y = f(x) + 3 is translated
Answer: 3 units up
Adding a constant outside the function shifts the graph vertically upward by 3.
The graph of y = 3f(x) is obtained from the graph of y = f(x) by which single transformation?
Answer: A vertical stretch, scale factor 3
Multiplying the output f(x) by 3 triples every y-coordinate, which is a vertical stretch with scale factor 3; the x-coordinates are unchanged.
The graph of y = f(x + 2) − 5 is obtained from the graph of y = f(x) by a translation with vector
Answer: (−2, −5)
Replacing x by x + 2 shifts the graph 2 units left, and subtracting 5 shifts it 5 units down, giving the vector (−2, −5).
The graph of y = x² is transformed to give y = (x − 4)² + 1. State the coordinates of the vertex of the new graph.
Answer: (4, 1)
The transformation translates the vertex (0, 0) by 4 units right and 1 unit up, so the new vertex is (4, 1); the sign inside the bracket works opposite to intuition.
The point P(6, −2) lies on the graph of y = f(x). Determine the coordinates of the image of P on the graph of y = 2f(x/3).
Answer: (18, −4)
f(x/3) is a horizontal stretch with scale factor 3 (x: 6 → 18) and the factor 2 is a vertical stretch (y: −2 → −4), giving (18, −4).
Which sequence of transformations maps the graph of y = x² onto the graph of y = 2(x + 3)²?
Answer: Translation 3 units left, then vertical stretch scale factor 2
Replacing x by x + 3 translates the graph 3 units left to give (x + 3)², and multiplying by 2 is a vertical stretch with scale factor 2.
That was 6 of 36 Transformations of graphs questions.
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