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IB Mathematics: Analysis and Approaches · Functions

Transformations of graphs practice questions.

36 exam-style questions on Transformations of graphs — topic 2.10 of Functions in the IB Mathematics: Analysis and Approaches syllabus — with answers and explanations. Samples below; the full set is free with an account.

At a glance

About this topic

Syllabus code
2.10
Subject
IB Mathematics: Analysis and Approaches
Topic
2 · Functions
Questions
36 with worked answers
Question types
14 multiple-choice questions · 8 fill-in-the-gap questions · 6 true/false questions · 4 flashcards · 3 diagram tasks · 1 matching task
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Sample questions on Transformations of graphs

Compared with y = f(x), the graph of y = f(x) + 3 is translated

  • 3 units up
  • 3 units down
  • 3 units right
  • 3 units left

Answer: 3 units up

Adding a constant outside the function shifts the graph vertically upward by 3.

The graph of y = 3f(x) is obtained from the graph of y = f(x) by which single transformation?

  • A horizontal stretch, scale factor 3
  • A vertical stretch, scale factor 3
  • A vertical stretch, scale factor 1/3
  • A translation of 3 units upwards

Answer: A vertical stretch, scale factor 3

Multiplying the output f(x) by 3 triples every y-coordinate, which is a vertical stretch with scale factor 3; the x-coordinates are unchanged.

The graph of y = f(x + 2) − 5 is obtained from the graph of y = f(x) by a translation with vector

  • (−2, −5)
  • (2, −5)
  • (−2, 5)
  • (2, 5)

Answer: (−2, −5)

Replacing x by x + 2 shifts the graph 2 units left, and subtracting 5 shifts it 5 units down, giving the vector (−2, −5).

The graph of y = x² is transformed to give y = (x − 4)² + 1. State the coordinates of the vertex of the new graph.

  • (−4, 1)
  • (4, −1)
  • (4, 1)
  • (−4, −1)

Answer: (4, 1)

The transformation translates the vertex (0, 0) by 4 units right and 1 unit up, so the new vertex is (4, 1); the sign inside the bracket works opposite to intuition.

The point P(6, −2) lies on the graph of y = f(x). Determine the coordinates of the image of P on the graph of y = 2f(x/3).

  • (2, −4)
  • (18, −1)
  • (2, −1)
  • (18, −4)

Answer: (18, −4)

f(x/3) is a horizontal stretch with scale factor 3 (x: 6 → 18) and the factor 2 is a vertical stretch (y: −2 → −4), giving (18, −4).

Which sequence of transformations maps the graph of y = x² onto the graph of y = 2(x + 3)²?

  • Translation 3 units right, then vertical stretch scale factor 2
  • Translation 3 units left, then vertical stretch scale factor 2
  • Vertical stretch scale factor 1/2, then translation 3 units right
  • Translation 3 units left, then horizontal stretch scale factor 2

Answer: Translation 3 units left, then vertical stretch scale factor 2

Replacing x by x + 3 translates the graph 3 units left to give (x + 3)², and multiplying by 2 is a vertical stretch with scale factor 2.

That was 6 of 36 Transformations of graphs questions.

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36 Transformations of graphs questions — free with an account. Spaced repetition, streaks and full exam simulations included.

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