36 exam-style questions on Graph of a function; sketching with technology — topic 2.3 of Functions in the IB Mathematics: Analysis and Approaches syllabus — with answers and explanations. Samples below; the full set is free with an account.
Let f(x) = x² − 3x. Determine which of the following points lies on the graph of y = f(x).
Answer: (2, −2)
A point (a, b) lies on the graph exactly when f(a) = b. Here f(2) = 4 − 6 = −2, so (2, −2) is on the graph.
The point (a, b) lies on the graph of y = f(x). State which condition must be satisfied.
Answer: f(a) = b
The graph of y = f(x) consists of all points (x, f(x)), so (a, b) is on the graph precisely when f(a) = b. Swapping input and output is a classic error.
Determine which of the following graphs never goes below the x-axis.
Answer: y = x²
x² ≥ 0 for all real x, so the graph of y = x² touches the x-axis at the origin but never goes below it. Subtracting 1 shifts the graph down, so y = x² − 1 does dip below.
The depth of water at a harbour rises and falls with the tide, repeating the same pattern about every 12 hours. Suggest which type of function is most appropriate for sketching depth against time.
Answer: Sinusoidal
A repeating rise-and-fall pattern is periodic, so a sinusoidal (sine or cosine) model matches the context; the other models are not periodic.
Let f(x) = x², g(x) = 2x and h(x) = f(x) + g(x). Calculate h(3).
Answer: 15
h(3) = f(3) + g(3) = 9 + 6 = 15. Using only f(3) = 9 or only g(3) = 6, or multiplying instead of adding, gives the distractors.
A ball is thrown vertically upwards and falls back to the ground. Suggest the shape of the graph of its height against time.
Answer: A parabola opening downwards
Height increases, reaches a maximum, then decreases symmetrically under constant gravity — a downward-opening parabola.
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