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IB Mathematics: Applications and Interpretation · Functions

Modelling: linear, quadratic, exponential, direct/inverse variation, cubic, sinusoidal practice questions.

36 exam-style questions on Modelling: linear, quadratic, exponential, direct/inverse variation, cubic, sinusoidal — topic 2.5 of Functions in the IB Mathematics: Applications and Interpretation syllabus — with answers and explanations. Samples below; the full set is free with an account.

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About this topic

Syllabus code
2.5
Subject
IB Mathematics: Applications and Interpretation
Topic
2 · Functions
Questions
36 with worked answers
Question types
16 fill-in-the-gap questions · 12 multiple-choice questions · 3 diagram tasks · 2 true/false questions · 1 flashcard · 1 matching task · 1 structured question
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Sample questions on Modelling: linear, quadratic, exponential, direct/inverse variation, cubic, sinusoidal

Solve the quadratic equation x² − 5x + 6 = 0.

  • x = 1 or x = 6
  • x = 2 or x = 3
  • x = −2 or x = −3
  • x = 1 or x = 5

Answer: x = 2 or x = 3

Factorising: (x − 2)(x − 3) = 0, so x = 2 or x = 3 (they sum to 5 and multiply to 6).

The height of a ball is modelled by h(t) = −5t² + 20t, with h in metres and t in seconds. Determine the maximum height reached.

  • 20 m
  • 15 m
  • 25 m
  • 40 m

Answer: 20 m

The maximum occurs at t = −b/(2a) = 20/10 = 2 s; h(2) = −5(4) + 40 = −20 + 40 = 20 m.

The value of a car is modelled by V(t) = 24000 × 0.85^t, with t in years. Calculate its value after 2 years, to the nearest dollar.

  • $17 340
  • $20 400
  • $16 320
  • $18 000

Answer: $17 340

V(2) = 24000 × 0.85² = 24000 × 0.7225 = 17 340.

The depth of water is modelled by d(t) = 6 + 3sin(30t°), with t in hours. State the minimum depth.

  • 3
  • 6
  • 9
  • 0

Answer: 3

sin ranges from −1 to 1, so the minimum of d is 6 + 3(−1) = 3.

A cubic model gives the volume of a box as V(x) = x(10 − 2x)(8 − 2x). Calculate V when x = 2.

  • 48
  • 24
  • 96
  • 12

Answer: 48

V(2) = 2 × (10 − 4) × (8 − 4) = 2 × 6 × 4 = 48.

The temperature of a cooling drink is modelled by T(t) = 20 + 60 × 0.5^t, with t in minutes. Determine the temperature it approaches after a long time.

  • 20°C
  • 80°C
  • 0°C
  • 60°C

Answer: 20°C

As t → ∞, 0.5^t → 0, so T → 20 + 0 = 20°C, the ambient temperature (horizontal asymptote).

That was 6 of 36 Modelling: linear, quadratic, exponential, direct/inverse variation, cubic, sinusoidal questions.

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36 Modelling: linear, quadratic, exponential, direct/inverse variation, cubic, sinusoidal questions — free with an account. Spaced repetition, streaks and full exam simulations included.

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