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IB Mathematics: Applications and Interpretation · Functions

Further models: natural log, logistic, piecewise, half-life practice questions.

27 exam-style questions on Further models: natural log, logistic, piecewise, half-life — topic 2.9 of Functions in the IB Mathematics: Applications and Interpretation syllabus — with answers and explanations. Samples below; the full set is free with an account.

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About this topic

Syllabus code
2.9
Subject
IB Mathematics: Applications and Interpretation
Topic
2 · Functions
Questions
27 with worked answers
Question types
9 multiple-choice questions · 8 fill-in-the-gap questions · 4 true/false questions · 3 flashcards · 2 structured questions · 1 matching task
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Sample questions on Further models: natural log, logistic, piecewise, half-life

A radioactive isotope has a half-life of 8 days. An initial sample of 240 g decays according to A(t) = 240 × (1/2)^(t/8). Calculate the mass remaining after 24 days.

  • 30 g
  • 60 g
  • 80 g
  • 120 g

Answer: 30 g

24 days is 3 half-lives (24/8 = 3), so the mass halves three times: 240 → 120 → 60 → 30 g.

A logistic model P(t) = L / (1 + Ce^(−kt)) describes population growth. State what the parameter L represents.

  • The initial population
  • The carrying capacity
  • The growth rate
  • The time to reach half the maximum

Answer: The carrying capacity

As t → ∞, the exponential term vanishes and P(t) → L, so L is the carrying capacity or maximum sustainable population.

The temperature of a cooling drink is modelled by T(t) = 20 + 60e^(−0.05t), where t is in minutes. State the temperature the drink approaches as t becomes very large.

  • 0 °C
  • 20 °C
  • 60 °C
  • 80 °C

Answer: 20 °C

As t → ∞, e^(−0.05t) → 0, so T → 20 °C, the ambient (room) temperature.

A quantity grows so that its natural-log model is y = 3 ln(x) + 5. Calculate y when x = e² (give an exact value).

  • 11
  • 8
  • 13
  • 6

Answer: 11

ln(e²) = 2, so y = 3(2) + 5 = 11.

A piecewise function is defined by f(x) = 2x + 1 for x < 3 and f(x) = x² − 2 for x ≥ 3. Calculate f(3).

  • 7
  • 6
  • 5
  • 9

Answer: 7

Since x = 3 satisfies x ≥ 3, use the second piece: f(3) = 3² − 2 = 9 − 2 = 7.

A sample of a substance decays with half-life 5 years. Determine the fraction of the original amount remaining after 15 years.

  • 1/8
  • 1/16
  • 1/6
  • 1/4

Answer: 1/8

15/5 = 3 half-lives, so the remaining fraction is (1/2)³ = 1/8.

That was 6 of 27 Further models: natural log, logistic, piecewise, half-life questions.

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27 Further models: natural log, logistic, piecewise, half-life questions — free with an account. Spaced repetition, streaks and full exam simulations included.

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