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IB Mathematics: Analysis and Approaches · Geometry and Trigonometry

Vector equation of a line (2D/3D) practice questions.

27 exam-style questions on Vector equation of a line (2D/3D) — topic 3.14 of Geometry and Trigonometry in the IB Mathematics: Analysis and Approaches syllabus — with answers and explanations. Samples below; the full set is free with an account.

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About this topic

Syllabus code
3.14
Subject
IB Mathematics: Analysis and Approaches
Topic
3 · Geometry and Trigonometry
Questions
27 with worked answers
Question types
10 multiple-choice questions · 8 fill-in-the-gap questions · 5 true/false questions · 3 flashcards · 1 matching task
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Sample questions on Vector equation of a line (2D/3D)

A line has vector equation r = (2, 1, 3) + λ(1, −1, 2). Which of the following points lies on the line?

  • (3, 0, 4)
  • (4, −1, 7)
  • (0, 3, 0)
  • (5, −2, 8)

Answer: (4, −1, 7)

With λ = 2: (2 + 2, 1 − 2, 3 + 4) = (4, −1, 7). Each other point matches at most two coordinates for a single value of λ.

Determine a direction vector for the line passing through the points P(2, 1, 0) and Q(5, −1, 4).

  • (3, −2, 4)
  • (7, 0, 4)
  • (3, 2, 4)
  • (−3, −2, 4)

Answer: (3, −2, 4)

A direction vector is PQ = Q − P = (5 − 2, −1 − 1, 4 − 0) = (3, −2, 4). Adding the coordinates instead of subtracting gives the trap (7, 0, 4).

A line has vector equation r = (1, 2, 3) + λ(2, 1, −1). Determine its Cartesian equations.

  • (x + 1)/2 = y + 2 = (z + 3)/(−1)
  • (x − 2)/1 = (y − 1)/2 = (z + 1)/3
  • (x − 1)/2 = y − 2 = (z − 3)/(−1)
  • (x − 1)/2 = y − 2 = z − 3

Answer: (x − 1)/2 = y − 2 = (z − 3)/(−1)

Solve each parametric equation for λ: λ = (x − 1)/2 = (y − 2)/1 = (z − 3)/(−1). Watch the signs: the point coordinates are subtracted and the direction components divide.

The lines r = (1, 0) + s(1, 2) and r = (4, 3) + t(−1, 1) intersect. Determine the point of intersection.

  • (2, 4)
  • (4, 3)
  • (3, 2)
  • (3, 4)

Answer: (3, 4)

Equating components: 1 + s = 4 − t and 2s = 3 + t give s = 2, t = 1, so the point is (1 + 2, 0 + 4) = (3, 4).

Consider the lines L₁: r = (1, 1, 1) + s(2, −1, 3) and L₂: r = (0, 3, 2) + t(−4, 2, −6). Determine the relationship between L₁ and L₂.

  • They are parallel and distinct
  • They intersect at exactly one point
  • They are the same line
  • They are skew

Answer: They are parallel and distinct

(−4, 2, −6) = −2(2, −1, 3), so the lines are parallel; since (1, 1, 1) does not satisfy the equation of L₂, they are distinct parallel lines.

Consider the lines L₁: r = (1, 0, 0) + s(1, 1, 0) and L₂: r = (0, 0, 1) + t(0, 1, −1). Determine the relationship between L₁ and L₂.

  • Parallel
  • Coincident
  • Intersecting
  • Skew

Answer: Skew

The direction vectors are not parallel, and solving 1 + s = 0, s = t, 0 = 1 − t gives t = −1 from the y-equation but t = 1 from the z-equation — no consistent solution, so the lines are skew.

That was 6 of 27 Vector equation of a line (2D/3D) questions.

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