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IB Mathematics: Analysis and Approaches

Geometry and Trigonometry practice questions.

612 exam-style questions on Geometry and Trigonometry with answers and explanations. Six real samples below — the full set is free with an account.

Syllabus

Topics covered

Key terms

Definitions you need

the angle of elevation
The angle measured upwards from the horizontal to the line of sight from an observer to an object above the horizontal level of the observer.
a three-figure bearing
The direction to a point measured as an angle clockwise from north, written with three digits (e.g. 060°, 245°).
skew lines
Skew lines are lines in three-dimensional space that are not parallel and do not intersect. They do not lie in a common plane, so they can only occur in three (or more) dimensions.
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Sample questions

Which expression equals sin(A + B)?

  • sin A cos B + cos A sin B
  • sin A cos B − cos A sin B
  • cos A cos B − sin A sin B
  • sin A sin B + cos A cos B

Answer: sin A cos B + cos A sin B

Compound-angle identity: sin(A+B) = sin A cos B + cos A sin B. For sine the sign matches the sign in the angle; for cosine it flips: cos(A+B) = cos A cos B − sin A sin B.

What is the angle between the vectors a = (1, 1, 0) and b = (1, 0, 0)?

  • 30°
  • 45°
  • 60°
  • 90°

Answer: 45°

cos θ = (a · b)/(|a||b|) = 1/(√2 × 1) = 1/√2, so θ = 45°. Always divide the dot product by both magnitudes.

A plane has normal vector n = (2, −1, 2) and passes through the point (1, 0, 3). Which is its Cartesian equation?

  • 2x − y + 2z = 8
  • 2x − y + 2z = 0
  • x + 3z = 8
  • 2x − y + 2z = 6

Answer: 2x − y + 2z = 8

Use r · n = a · n: the right-hand side is 2(1) − 1(0) + 2(3) = 8, giving 2x − y + 2z = 8. Substitute the point back in to verify.

A circle has radius 5 cm. The length of an arc subtending an angle of 1.2 radians at the centre is

  • 4.2 cm
  • 6 cm
  • 7.5 cm
  • 12 cm

Answer: 6 cm

With the angle in radians, arc length s = rθ = 5 × 1.2 = 6 cm. This simple formula is a key reason radians are used.

Find the area of a circle with radius 5 (leave your answer in terms of π).

  • 10π
  • 25π
  • 5π
  • 50π

Answer: 25π

Area = πr² = π × 5² = 25π.

The period of f(x) = sin(2x) is

  • π/2
  • π
  • 2π
  • 4π

Answer: π

For sin(bx) the period is 2π / b. Here b = 2, so the period is 2π / 2 = π.

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