77 exam-style questions on Electric and magnetic fields — topic D.2 of Fields in the IB Physics syllabus — with answers and explanations. Samples below; the full set is free with an account.
The electrostatic force between two point charges is F. The separation between them is tripled while the charges remain unchanged. State the new force.
Answer: F/9
Coulomb's law is an inverse-square law: F ∝ 1/r², so tripling the separation reduces the force by a factor of 3² = 9.
Two parallel plates separated by 4.0 mm are connected to a 200 V supply. Calculate the electric field strength between the plates.
Answer: 5.0 × 10⁴ V m⁻¹
For a uniform field E = V/d = 200 / (4.0 × 10⁻³) = 5.0 × 10⁴ V m⁻¹. A common error is forgetting to convert mm to m.
A uniform electric field points due east. Determine the direction of the electric force acting on an electron placed in this field.
Answer: West
The field direction is defined by the force on a positive charge; the electron is negative, so the force on it is opposite to the field, i.e. due west.
Which statement best describes the magnetic field pattern produced by a long straight wire carrying a constant current?
Answer: Concentric circles around the wire, in planes perpendicular to it
The field forms closed circular loops centred on the wire; their direction is given by the right-hand grip rule and the field weakens with distance from the wire.
Electric charge is quantised. Which value CANNOT be the total charge of an isolated object? (e = 1.6 × 10⁻¹⁹ C)
Answer: 2.4 × 10⁻¹⁹ C
Charge only occurs in whole-number multiples of e; 2.4 × 10⁻¹⁹ C would correspond to 1.5e, which is impossible for an isolated object.
Two equal positive point charges are held a fixed distance apart. State the electric field strength at the midpoint between them.
Answer: Zero
At the midpoint the two fields have equal magnitude but point in opposite directions, so they cancel exactly and the resultant field is zero.
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