27 exam-style questions on Complex numbers: Cartesian form; complex plane; quadratic solutions — topic 1.12 of Number and Algebra in the IB Mathematics: Applications and Interpretation syllabus — with answers and explanations. Samples below; the full set is free with an account.
Given z = 3 + 4i, calculate the modulus |z|.
Answer: 5
|z| = √(3² + 4²) = √(9 + 16) = √25 = 5.
Determine the value of (2 + 3i) + (4 − 5i).
Answer: 6 − 2i
Add real and imaginary parts separately: (2 + 4) + (3 − 5)i = 6 − 2i.
Calculate the product (2 + i)(3 − 2i).
Answer: 8 − i
(2 + i)(3 − 2i) = 6 − 4i + 3i − 2i² = 6 − i + 2 = 8 − i, using i² = −1.
The quadratic equation x² − 4x + 13 = 0 has complex roots. Determine the roots.
Answer: 2 ± 3i
x = (4 ± √(16 − 52))/2 = (4 ± √(−36))/2 = (4 ± 6i)/2 = 2 ± 3i.
State the complex conjugate of z = −5 + 2i.
Answer: −5 − 2i
The conjugate negates only the imaginary part: z* = −5 − 2i.
A complex number z is plotted in the complex plane at the point (−3, 4), where the horizontal axis is real and the vertical axis is imaginary. State z in Cartesian form.
Answer: −3 + 4i
The real part is the horizontal coordinate (−3) and the imaginary part is the vertical coordinate (4), so z = −3 + 4i.
That was 6 of 27 Complex numbers: Cartesian form; complex plane; quadratic solutions questions.
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27 Complex numbers: Cartesian form; complex plane; quadratic solutions questions — free with an account. Spaced repetition, streaks and full exam simulations included.
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