28 exam-style questions on First principles; higher derivatives — topic 5.12 of Calculus in the IB Mathematics: Analysis and Approaches syllabus — with answers and explanations. Samples below; the full set is free with an account.
In a first-principles differentiation of f(x) = x², the quotient (f(x + h) − f(x)) / h simplifies, before the limit is taken, to:
Answer: 2x + h
(x + h)² − x² = 2xh + h², and dividing by h gives 2x + h; the limit h → 0 then yields f′(x) = 2x.
When differentiating f(x) = 1/x from first principles, the quotient (f(x + h) − f(x)) / h simplifies, before the limit is taken, to:
Answer: −1 / (x(x + h))
1/(x + h) − 1/x = −h/(x(x + h)); dividing by h leaves −1/(x(x + h)), which tends to −1/x² as h → 0.
Determine the third derivative f⁽³⁾(x) of f(x) = x⁴.
Answer: 24x
Differentiating repeatedly: f′(x) = 4x³, f″(x) = 12x², f⁽³⁾(x) = 24x; the constant 24 is the fourth derivative.
Let y = e²ˣ. Determine an expression for the nth derivative dⁿy/dxⁿ.
Answer: 2ⁿ e²ˣ
Each differentiation multiplies by the factor 2 from the chain rule, so after n differentiations the result is 2ⁿ e²ˣ.
Let f(x) = sin x. Determine f⁽²⁰²⁶⁾(x), the 2026th derivative of f.
Answer: −sin x
The derivatives of sin x cycle with period 4: cos x, −sin x, −cos x, sin x. Since 2026 = 4 × 506 + 2, the 2026th derivative equals the second, −sin x.
Let y = ln x, x > 0. Determine d²y/dx².
Answer: −1/x²
dy/dx = 1/x = x⁻¹, so d²y/dx² = −x⁻² = −1/x²; forgetting the negative sign from the power rule is a common error.
That was 6 of 28 First principles; higher derivatives questions.
Practise all 28 freeA student differentiates f(x) = x³ from first principles: step 1 writes [(x + h)³ − x³]/h; step 2 expands it to (3x²h + 3xh² + h³)/h; step 3 simplifies to 3x² + 3xh + h²; step 4 concludes f′(x) = 3x² + 3xh.
See the correction →28 First principles; higher derivatives questions — free with an account. Spaced repetition, streaks and full exam simulations included.
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