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IB Mathematics: Analysis and Approaches · Calculus

Definite integrals; areas between curves practice questions.

65 exam-style questions on Definite integrals; areas between curves — topic 5.11 of Calculus in the IB Mathematics: Analysis and Approaches syllabus — with answers and explanations. Samples below; the full set is free with an account.

At a glance

About this topic

Syllabus code
5.11
Subject
IB Mathematics: Analysis and Approaches
Topic
5 · Calculus
Questions
65 with worked answers
Question types
43 fill-in-the-gap questions · 10 multiple-choice questions · 6 true/false questions · 4 flashcards · 1 diagram task · 1 matching task
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Sample questions on Definite integrals; areas between curves

Calculate ∫ (2x + 1) dx between x = 1 and x = 4.

  • 15
  • 21
  • 18
  • 12

Answer: 18

An antiderivative is x² + x, so the integral equals (16 + 4) − (1 + 1) = 20 − 2 = 18.

Determine the area of the region enclosed by the line y = x and the curve y = x² between their points of intersection.

  • 1/6
  • 1/3
  • 1/2
  • 5/6

Answer: 1/6

The graphs meet at x = 0 and x = 1, with the line above the curve, so A = ∫₀¹ (x − x²) dx = 1/2 − 1/3 = 1/6.

Given that ∫₂⁵ f(x) dx = 7 and ∫₂⁵ g(x) dx = 3, determine the value of ∫₂⁵ (2f(x) − g(x)) dx.

  • 4
  • 8
  • 17
  • 11

Answer: 11

By linearity of the integral, the value is 2(7) − 3 = 11.

Calculate ∫ sin x dx between x = 0 and x = π.

  • 0
  • 2
  • −2
  • 1

Answer: 2

An antiderivative of sin x is −cos x, so the integral is −cos π − (−cos 0) = 1 + 1 = 2.

The constant k > 1 satisfies ∫₁ᵏ (1/x) dx = ln 5. Determine the value of k.

  • 5
  • e⁵
  • ln 5
  • 25

Answer: 5

∫₁ᵏ (1/x) dx = ln k − ln 1 = ln k, so ln k = ln 5 gives k = 5.

Determine the area of the region enclosed by the curve y = 4 − x² and the x-axis.

  • 16/3
  • 64/3
  • 32/3
  • 8/3

Answer: 32/3

The curve meets the x-axis at x = ±2, so A = ∫₋₂² (4 − x²) dx = (8 − 8/3) − (−8 + 8/3) = 32/3.

That was 6 of 65 Definite integrals; areas between curves questions.

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