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Standing waves and resonance practice questions.

66 exam-style questions on Standing waves and resonance — topic C.4 of Wave behaviour in the IB Physics syllabus — with answers and explanations. Samples below; the full set is free with an account.

At a glance

About this topic

Syllabus code
C.4
Subject
IB Physics
Theme
C · Wave behaviour
Questions
66 with worked answers
Question types
37 fill-in-the-gap questions · 13 multiple-choice questions · 7 true/false questions · 6 flashcards · 1 diagram task · 1 matching task · 1 structured question
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Sample questions on Standing waves and resonance

A string of length 0.60 m is fixed at both ends. Waves travel along the string at 120 m s⁻¹. Calculate the frequency of the first harmonic.

  • 50 Hz
  • 200 Hz
  • 400 Hz
  • 100 Hz

Answer: 100 Hz

For a string fixed at both ends the first-harmonic wavelength is 2L = 1.2 m, so f₁ = v/2L = 120/1.2 = 100 Hz.

A pipe is closed at one end and open at the other. Which harmonics can be set up in the air column of the pipe?

  • Only even harmonics
  • All harmonics
  • Only odd harmonics
  • Only the first harmonic

Answer: Only odd harmonics

A closed end must be a displacement node and an open end an antinode, which is only possible for odd multiples of the first-harmonic frequency (n = 1, 3, 5, …).

P and Q are two oscillating points on a standing wave. They lie on opposite sides of the same node, each less than a quarter of a wavelength from it. What is the phase difference between the oscillations of P and Q?

  • π rad
  • π/2 rad
  • 0
  • 2π rad

Answer: π rad

Points in adjacent loops of a standing wave move in opposite directions at every instant, so they oscillate in antiphase: phase difference π rad.

Adjacent nodes of a standing wave on a stretched wire are separated by 0.40 m. The wire oscillates at a frequency of 425 Hz. Determine the speed of the waves travelling along the wire.

  • 170 m s⁻¹
  • 340 m s⁻¹
  • 680 m s⁻¹
  • 85 m s⁻¹

Answer: 340 m s⁻¹

The node-to-node distance is half a wavelength, so λ = 0.80 m and v = fλ = 425 × 0.80 = 340 m s⁻¹.

A pipe of length 0.50 m is open at both ends. The speed of sound in air is 340 m s⁻¹. What is the frequency of the third harmonic of the pipe?

  • 340 Hz
  • 510 Hz
  • 680 Hz
  • 1020 Hz

Answer: 1020 Hz

For a pipe open at both ends f₁ = v/2L = 340/1.0 = 340 Hz, so the third harmonic is 3f₁ = 1020 Hz.

Which feature distinguishes a standing wave from a travelling wave?

  • Energy is continuously transferred through the medium at the full wave speed
  • The amplitude of oscillation depends on position along the medium
  • All points oscillate with the same amplitude
  • The wave profile moves through the medium

Answer: The amplitude of oscillation depends on position along the medium

In a standing wave the amplitude varies from zero at nodes to a maximum at antinodes, and no net energy is transferred along the medium.

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