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Practice questionsIB PhysicsThe particulate nature of matter
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The particulate nature of matter practice questions.

165 exam-style questions on The particulate nature of matter with answers and explanations. Six real samples below — the full set is free with an account.

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In the kinetic theory of gases, the absolute temperature of an ideal gas is proportional to the average...

  • speed of the molecules
  • kinetic energy of the molecules
  • potential energy of the molecules
  • size of the molecules

Answer: kinetic energy of the molecules

Average translational KE = (3/2)kT, so temperature (in kelvin) is proportional to the average kinetic energy of the molecules.

Which statement correctly distinguishes an isothermal from an adiabatic process for an ideal gas?

  • Isothermal: ΔU = 0 (Q = W); Adiabatic: Q = 0 (ΔU = −W)
  • Isothermal: Q = 0; Adiabatic: ΔU = 0
  • Both of these processes always have exactly Q = 0 throughout the whole change
  • Both have ΔU = 0

Answer: Isothermal: ΔU = 0 (Q = W); Adiabatic: Q = 0 (ΔU = −W)

Isothermal keeps T constant so ΔU = 0 and Q = W. Adiabatic exchanges no heat (Q = 0) so any work changes internal energy: ΔU = −W.

A fixed mass of ideal gas is held at constant volume while its absolute (kelvin) temperature is doubled. Its pressure will

  • halve
  • stay the same
  • double
  • quadruple

Answer: double

At constant volume p ∝ T (Gay-Lussac's law), so doubling the kelvin temperature doubles the pressure.

Two 6.0 Ω resistors are connected in parallel. Their combined resistance is

  • 3.0 Ω
  • 6.0 Ω
  • 12 Ω
  • 0.33 Ω

Answer: 3.0 Ω

1/R = 1/6.0 + 1/6.0 = 2/6.0, so R = 3.0 Ω. Two equal resistors in parallel give half the value of one.

The radiation emitted by a black body has maximum intensity at a wavelength of 580 nm. Using Wien's displacement law (constant = 2.9 × 10⁻³ m K), the surface temperature of the body is approximately:

  • 500 K
  • 2900 K
  • 50 000 K
  • 5000 K

Answer: 5000 K

T = 2.9 × 10⁻³ / (580 × 10⁻⁹) = 5000 K. Power-of-ten slips give 500 K or 50 000 K; hotter bodies peak at shorter wavelengths.

The absolute temperature of a black body is doubled while its surface area stays constant. The total power it radiates increases by a factor of:

  • 2
  • 4
  • 8
  • 16

Answer: 16

The Stefan–Boltzmann law gives P = σAT⁴, so doubling T multiplies the power by 2⁴ = 16. Choosing 2 or 4 comes from forgetting the fourth-power dependence.

165 The particulate nature of matter questions — free with an account. Spaced repetition, streaks and full exam simulations included.

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