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The particulate nature of matter practice questions.

343 exam-style questions on The particulate nature of matter with answers and explanations. Six real samples below — the full set is free with an account.

Syllabus

Topics covered

Key terms

Definitions you need

the specific latent heat of fusion of a substance
The energy required to change 1 kg of the substance from solid to liquid at constant temperature (its melting point).
the electromotive force (EMF) of a cell
The total energy transferred from chemical to electrical form per unit charge driven around the complete circuit by the cell.
specific latent heat
The energy required to change the phase of 1 kg of a substance at constant temperature.
the internal energy of an ideal gas
The total random kinetic energy of all the molecules of the gas.
the solar constant
The solar constant S is the intensity of the Sun's radiation arriving at the top of Earth's atmosphere, at the mean Earth–Sun distance, measured on a surface perpendicular to the rays. S ≈ 1360 W/m².
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Sample questions

In the kinetic theory of gases, the absolute temperature of an ideal gas is proportional to the average...

  • speed of the molecules
  • kinetic energy of the molecules
  • potential energy of the molecules
  • size of the molecules

Answer: kinetic energy of the molecules

Average translational KE = (3/2)kT, so temperature (in kelvin) is proportional to the average kinetic energy of the molecules.

Which statement correctly distinguishes an isothermal from an adiabatic process for an ideal gas?

  • Isothermal: ΔU = 0 (Q = W); Adiabatic: Q = 0 (ΔU = −W)
  • Isothermal: Q = 0; Adiabatic: ΔU = 0
  • Both of these processes always have exactly Q = 0 throughout the whole change
  • Both have ΔU = 0

Answer: Isothermal: ΔU = 0 (Q = W); Adiabatic: Q = 0 (ΔU = −W)

Using Q = ΔU + W, where W is the work done by the gas: isothermal keeps T constant, so ΔU = 0 and Q = W; adiabatic exchanges no heat (Q = 0), so ΔU = −W. Swapping the two conditions gives the most tempting wrong option.

A fixed mass of ideal gas is held at constant volume while its absolute (kelvin) temperature is doubled. Its pressure will

  • halve
  • stay the same
  • double
  • quadruple

Answer: double

At constant volume p ∝ T (Gay-Lussac's law), so doubling the kelvin temperature doubles the pressure.

Two 6.0 Ω resistors are connected in parallel. Their combined resistance is

  • 3.0 Ω
  • 6.0 Ω
  • 12 Ω
  • 0.33 Ω

Answer: 3.0 Ω

1/R = 1/6.0 + 1/6.0 = 2/6.0, so R = 3.0 Ω. Two equal resistors in parallel give half the value of one.

The radiation emitted by a black body has maximum intensity at a wavelength of 580 nm. Using Wien's displacement law (constant = 2.9 × 10⁻³ m K), the surface temperature of the body is approximately:

  • 500 K
  • 2900 K
  • 50 000 K
  • 5000 K

Answer: 5000 K

T = 2.9 × 10⁻³ / (580 × 10⁻⁹) = 5000 K. Power-of-ten slips give 500 K or 50 000 K; hotter bodies peak at shorter wavelengths.

The absolute temperature of a black body is doubled while its surface area stays constant. The total power it radiates increases by a factor of:

  • 2
  • 4
  • 8
  • 16

Answer: 16

The Stefan–Boltzmann law gives P = σAT⁴, so doubling T multiplies the power by 2⁴ = 16. Choosing 2 or 4 comes from forgetting the fourth-power dependence.

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