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IB Mathematics: Applications and Interpretation · Statistics and Probability

Probability concepts; complementary events; expected occurrences practice questions.

36 exam-style questions on Probability concepts; complementary events; expected occurrences — topic 4.5 of Statistics and Probability in the IB Mathematics: Applications and Interpretation syllabus — with answers and explanations. Samples below; the full set is free with an account.

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About this topic

Syllabus code
4.5
Subject
IB Mathematics: Applications and Interpretation
Topic
4 · Statistics and Probability
Questions
36 with worked answers
Question types
12 fill-in-the-gap questions · 12 multiple-choice questions · 7 true/false questions · 3 flashcards · 2 matching tasks
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Sample questions on Probability concepts; complementary events; expected occurrences

The probability that it rains on a given day is P(R) = 0.35. Calculate the probability that it does not rain on that day.

  • 0.35
  • 0.65
  • 0.70
  • 1.35

Answer: 0.65

For complementary events, P(not R) = 1 - P(R) = 1 - 0.35 = 0.65.

A spinner lands on red with probability 0.2. If it is spun 150 times, calculate the expected number of times it lands on red.

  • 30
  • 75
  • 20
  • 120

Answer: 30

Expected occurrences = n × p = 150 × 0.2 = 30.

A bag contains 3 red, 5 blue and 2 green marbles. One marble is drawn at random. Determine the probability that it is NOT blue.

  • 1/2
  • 1/5
  • 7/10
  • 3/10

Answer: 1/2

P(blue) = 5/10, so P(not blue) = 1 - 5/10 = 5/10 = 1/2.

Two events A and B are mutually exclusive, with P(A) = 0.3 and P(B) = 0.45. Calculate P(A ∪ B).

  • 0.135
  • 0.75
  • 0.15
  • 0.60

Answer: 0.75

For mutually exclusive events P(A ∪ B) = P(A) + P(B) = 0.3 + 0.45 = 0.75, since P(A ∩ B) = 0.

In a class of 30 students, the probability that a randomly chosen student wears glasses is 0.4. Determine the expected number of students who do NOT wear glasses.

  • 12
  • 18
  • 0.6
  • 24

Answer: 18

P(no glasses) = 1 - 0.4 = 0.6; expected number = 30 × 0.6 = 18.

Events A and B satisfy P(A) = 0.5, P(B) = 0.4 and P(A ∩ B) = 0.2. Calculate P(A ∪ B).

  • 0.9
  • 1.1
  • 0.7
  • 0.2

Answer: 0.7

P(A ∪ B) = P(A) + P(B) - P(A ∩ B) = 0.5 + 0.4 - 0.2 = 0.7.

That was 6 of 36 Probability concepts; complementary events; expected occurrences questions.

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36 Probability concepts; complementary events; expected occurrences questions — free with an account. Spaced repetition, streaks and full exam simulations included.

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