27 exam-style questions on Unit circle definitions; Pythagorean identity; ambiguous case — topic 3.8 of Geometry and Trigonometry in the IB Mathematics: Applications and Interpretation syllabus — with answers and explanations. Samples below; the full set is free with an account.
State the exact value of cos(120°).
Answer: −1/2
120° lies in the second quadrant where cosine is negative; the reference angle is 60°, so cos(120°) = −cos(60°) = −1/2.
Given that sin θ = 3/5 and θ is obtuse, determine cos θ.
Answer: −4/5
By the Pythagorean identity cos²θ = 1 − 9/25 = 16/25, so cos θ = ±4/5; an obtuse angle is in the second quadrant where cosine is negative, giving −4/5.
In triangle ABC, angle A = 35°, side a = 6 cm and side b = 9 cm. Using the sine rule, this ambiguous case gives how many possible triangles?
Answer: 2
sin B = b·sin A / a = 9·sin35°/6 ≈ 0.860, so B ≈ 59.4° or 120.6°; since a < b and both values keep A + B < 180°, two triangles are possible.
Determine the exact value of tan(135°).
Answer: −1
135° is in the second quadrant where tangent is negative; the reference angle is 45°, so tan(135°) = −tan(45°) = −1.
The point where the terminal side of angle θ meets the unit circle has coordinates (−0.6, 0.8). State sin θ.
Answer: 0.8
On the unit circle the point is (cos θ, sin θ), so the y-coordinate 0.8 is sin θ.
Given cos θ = −0.28, calculate sin²θ.
Answer: 0.9216
By the Pythagorean identity sin²θ = 1 − cos²θ = 1 − 0.0784 = 0.9216.
That was 6 of 27 Unit circle definitions; Pythagorean identity; ambiguous case questions.
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27 Unit circle definitions; Pythagorean identity; ambiguous case questions — free with an account. Spaced repetition, streaks and full exam simulations included.
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