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IB Mathematics: Applications and Interpretation · Calculus

Phase portraits; eigenvalue analysis of trajectories practice questions.

27 exam-style questions on Phase portraits; eigenvalue analysis of trajectories — topic 5.17 of Calculus in the IB Mathematics: Applications and Interpretation syllabus — with answers and explanations. Samples below; the full set is free with an account.

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About this topic

Syllabus code
5.17
Subject
IB Mathematics: Applications and Interpretation
Topic
5 · Calculus
Questions
27 with worked answers
Question types
11 multiple-choice questions · 6 fill-in-the-gap questions · 5 true/false questions · 4 flashcards · 1 matching task
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Sample questions on Phase portraits; eigenvalue analysis of trajectories

A coupled system has matrix M = [[3, 0], [0, -2]]. Determine the nature of the equilibrium point at the origin.

  • Stable node (both trajectories decay to origin)
  • Saddle point
  • Unstable node (both trajectories move away)
  • Centre

Answer: Saddle point

The eigenvalues are 3 and -2. Real eigenvalues of opposite sign give a saddle point.

The matrix of a linear system is M = [[-4, 0], [0, -1]]. Determine the long-term behaviour of trajectories.

  • They spiral outward
  • Approach the origin: stable node
  • They all move away (unstable node)
  • They form closed loops

Answer: Approach the origin: stable node

Both eigenvalues (-4 and -1) are real and negative, so every trajectory decays to the origin: a stable node.

For the system with matrix M = [[2, 1], [0, 2]] the eigenvalues are both 2. State the nature of the origin.

  • Stable node
  • Saddle point
  • Unstable node
  • Stable spiral

Answer: Unstable node

A repeated real eigenvalue that is positive gives an unstable node; trajectories move away from the origin.

A system has complex eigenvalues λ = 1 ± 3i. Determine the type of equilibrium at the origin.

  • Stable spiral (sink)
  • Unstable spiral (source)
  • Centre
  • Saddle point (real eigenvalues of opposite sign)

Answer: Unstable spiral (source)

Complex eigenvalues with a positive real part (Re λ = 1 > 0) produce trajectories that spiral outward: an unstable spiral.

Find the eigenvalues of M = [[1, 2], [2, 1]].

  • λ = 1 and λ = 2
  • λ = 3 and λ = -1
  • λ = -3 and λ = 1
  • λ = 3 and λ = 1

Answer: λ = 3 and λ = -1

det(M − λI) = (1−λ)² − 4 = λ² − 2λ − 3 = (λ−3)(λ+1), giving λ = 3 and λ = −1.

The matrix M = [[0, -2], [2, 0]] has eigenvalues λ = ±2i. Determine the nature of the origin.

  • Stable node (real negative eigenvalues)
  • Unstable spiral
  • Saddle point
  • Centre (closed orbits)

Answer: Centre (closed orbits)

Purely imaginary eigenvalues (real part 0) give a centre: trajectories are closed loops around the origin.

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