36 exam-style questions on Simple deductive proof — topic 1.6 of Number and Algebra in the IB Mathematics: Analysis and Approaches syllabus — with answers and explanations. Samples below; the full set is free with an account.
In a deductive proof, which expression correctly represents a general even integer?
Answer: 2k, where k is an integer
Every even integer is a multiple of 2, so it is written 2k with k an integer; 2k + 1 represents an odd integer, and k + 2 has the same parity as k.
Which of the following is a valid deductive method for proving that an algebraic identity holds?
Answer: Start from one side and transform it algebraically, step by step, into the other side
A deductive proof must follow logically from accepted rules for all values, which working from one side to the other achieves; checking examples or assuming the result does not establish general truth.
For an integer n, which pair of expressions represents two consecutive odd integers?
Answer: 2n + 1 and 2n + 3
2n + 1 is odd for any integer n, and the next odd integer is two more: 2n + 3. Adding only 1 gives an even number, and 2n, 2n + 2 are consecutive even integers.
As part of a proof, a student expands (n + 3)² − (n − 3)², where n is an integer. Which simplified result is correct?
Answer: 12n
(n² + 6n + 9) − (n² − 6n + 9) = 12n; the n² and constant terms cancel while the middle terms combine. Forgetting that the constant 9 cancels gives the +18 distractor.
In the identity (x + 1)² ≡ x² + 2x + 1, what does the symbol ≡ indicate?
Answer: The two expressions are equal for every value of the variable
The identity symbol ≡ states that both sides are identically equal — equal for all values of x — unlike an equation, which may hold only for particular solutions.
To prove that the product of two even integers is divisible by 4, the integers are written as 2m and 2n. Which expression for their product completes the proof?
Answer: 4mn
2m × 2n = 4mn, and since mn is an integer, the product is a multiple of 4. Multiplying, not adding, the two factors is the essential step.
That was 6 of 36 Simple deductive proof questions.
Practise all 36 freeA student claims that every odd integer greater than 1 is prime.
See the correction →36 Simple deductive proof questions — free with an account. Spaced repetition, streaks and full exam simulations included.
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