50 exam-style questions on Mathematics — topic T3 of Skills in the study of ESS in the IB Environmental Systems and Societies syllabus — with answers and explanations. Samples below; the full set is free with an account.
The pH scale is logarithmic. If the water of a lake changes from pH 6.0 to pH 5.0, the concentration of hydrogen ions has
Answer: risen to ten times its earlier value
Each whole pH unit is a factor of ten in hydrogen ion concentration, so a fall of one unit is a tenfold rise in acidity. Reading a logarithmic scale as if it were linear badly understates how large the chemical change is.
Two sets of ten quadrat counts have the same mean of 24 plants, but set A has a standard deviation of 2 and set B a standard deviation of 11. This shows that
Answer: the counts in set B vary far more widely about the mean
Standard deviation measures the spread of the values about the mean, not the area sampled or the number of species. A large spread warns that the species is patchy and that a difference between two site means may be smaller than the variation within each site.
Nine nitrate readings from a stream lie between 2 and 6 mg dm-3, while a tenth, taken just after a slurry spill, is 61 mg dm-3. To describe the nitrate concentration typical of the stream it is best to quote
Answer: the median, because one extreme value distorts the mean
The single reading of 61 mg dm-3 pulls the mean above every other value, so the mean would misrepresent normal conditions; the median is resistant to such outliers. The spill should be reported separately rather than hidden inside an average.
Country X emits 480 Mt of carbon dioxide a year and has 60 million inhabitants; country Y emits 900 Mt and has 300 million inhabitants. Expressed per capita,
Answer: X emits more than twice as much per person as Y
Dividing by population gives 8 t per person for X and 3 t for Y, so the ranking by total emissions is the opposite of the ranking per person. Per capita figures are what make countries of very different size comparable.
A kick sample from a polluted stretch of river contains 40 individuals, all belonging to one species of tubificid worm. Using D = N(N - 1) / sum of n(n - 1), the value of Simpson's reciprocal diversity index for this sample is
Answer: 1.00, which is the lowest value the index can take
With one species, sum of n(n - 1) equals N(N - 1), so D = 1. The index has a floor of 1, not 0, and a higher value means a more diverse community.
In a study of pond snails, 50 snails are marked and released and 40 snails are caught in the second sample. The Lincoln index N = (n1 x n2) / n3 gives an estimated population of 250 snails. The number of marked snails in the second sample was
Answer: 8 snails
Rearranging N = (n1 x n2) / n3 gives n3 = (50 x 40) / 250 = 8. Working the formula backwards is the quickest check that a quoted population estimate is arithmetically possible.
That was 6 of 50 Mathematics questions.
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50 Mathematics questions — free with an account. Spaced repetition, streaks and full exam simulations included.
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